Concrete is one of the most commonly used building materials.
Concrete is a composite materialmade from several readily available constituents(aggregates, sand, cement, water).
Concrete is a versatile material that can easily be mixedto meet a variety of special needs and formed to virtually any shape.
Density of Cement = 1440 kg/m3
Sand Density = 1450-1500 kg/m3
Density of Aggregate = 1450-1550 kg/m3
How many KG in 1 bag of cement = 50 kg
Cement quantity in litres in 1 bag of cement = 34.7 litres
1 Bag of cement in cubic metres = 0.0347 cubic meter
How many CFT (Cubic Feet) = 1.226 CFT
Numbers of Bags in 1 cubic metre cement = 28.8 Bags
Specific gravity of cement = 3.15
Grade of cement = 33, 43, 53
Where 33, 43, 53 compressive strength of cement in N/mm2
M-20 = 1 : 1.5 : 3 = 5.5, (Cement : Sand : Aggregate)
Some of Mix is – 5.5
Where, M = Mix
20 = Characteristic Compressive strength
Consider volume of concrete = 1m3
Dry Volume of Concrete = 1 x 1.54 = 1.54 m3 (For Dry Volume Multiply By 1.54)
Cement= (1/5.5) x 1.54 = 0.28 m3 ∴ 1 is a part of cement, 5.5 is sum of ratio
Density of Cement is 1440/m3
= 0.28 x 1440 = 403.2 kg
We know each bag of cement is 50 kg
For Numbers of Bags = 403.2/50 = 8 Bags
We Know in one bag of cement = 1.226 CFT
For Calculate in CFT (Cubic Feet) = 8 x 1.225 = 9.8 Cubic Feet
Consider volume of concrete = 1m3
Dry Volume of Concrete = 1 x 1.54 = 1.54 m3
Sand= (1.5/5.5) x 1.54 = 0.42 m3 ∴ 1.5 is a part of Sand, 5.5 is sum of ratio
Density of Sand is 1450/m3
For KG = 0.42 x 1450 = 609 kg
As we know that 1m3 = 35.31 CFT
For Calculation in Cubic Feet = 0.42 x 35.31 = 14.83 Cubic Feet
Consider volume of concrete = 1m3
Dry Volume of Concrete = 1 x 1.54 = 1.54 m3
Aggregate = (3/5.5) x 1.54 = 0.84 m3 ∴ 3 is a part of cement, 5.5 is sum of ratio
Density of Aggregate is 1500/m3
Calculation for KG = 0.84 x 1500 = 1260 kg
As we know that 1 m3 = 35.31 CFT
Calculation for CFT = 0.84 x 35.31 = 29.66 Cubic Feet
Area of brick wall for plaster = 3m x 3m =9m2
Plaster Thickness = 12mm (Outer-20mm, Inner 12mm)
Volume of mortar = 9m2 0.012m = 0.108m3
Ratio for Plaster Taken is = 1 : 6
Sum of ratio is = 7
Calculation for Cement Volume
Dry Volume of Mortar = 0.108 1.35 = 0.1458 m3
Cement= (1/7) = 0.0208 m3
Density of Cement is 1440/m3
= 0 1440 = 29.99 kg
We know each bag of cement is 50 kg
= (29.99/50) = 0.599 Bags
Calculation for Sand Volume
Sand = (6/7) x 0.1458 = 0.124m3
Density of Sand is 1450/m3
= 0 1450 = 181.2 kg
Now we find how many CFT (Cubic feet) Required
As we know that 1m3 = 35.31 CFT
= 0.124*35.31
= 4.37 CFT (Cubic Feet)
Reference : tutorialstipscivil.com
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